<\/p>\n
L\u00f4 xi\u00ean l\u00e0 g\u00ec? B\u00ed quy\u1ebft ch\u01a1i l\u00f4 xi\u00ean gi\u00fap b\u1ea1n th\u1eafng l\u1edbn nh\u01b0ng l\u1ea1i \u0111\u01a1n gi\u1ea3n d\u1ec5 \u00e1p d\u1ee5ng. C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang khi ch\u01a1i l\u00f4 xi\u00ean nh\u01b0 th\u1ebf n\u00e0o. C\u00f9ng t\u00ecm hi\u1ec3u ngay b\u00e0i vi\u1ebft sau \u0111\u00e2y t\u1eeb c\u00e1c chuy\u00ean gia soi c\u1ea7u nh\u00e9.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n L\u00f4 xi\u00ean c\u00f2n \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 L\u00f4 x\u00e2u. L\u00e0 vi\u1ec7c b\u1ea1n ch\u01a1i 2 con l\u00f4, 3 con l\u00f4 ho\u1eb7c 4 con l\u00f4 c\u00f9ng 1 l\u00fac. N\u1ebfu nh\u01b0 c\u00e1c con s\u1ed1 b\u1ea1n \u0111\u00e1nh \u0111\u1ec1u xu\u1ea5t hi\u1ec7n trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc h\u00f4m \u0111\u00f3. Th\u00ec c\u00f3 ngh\u0129a l\u00e0 b\u1ea1n \u0103n l\u00f4 xi\u00ean.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n K\u1ebft qu\u1ea3 l\u00f4 l\u00e0 c\u00e1c con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a 27 gi\u1ea3i th\u01b0\u1edfng trong x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft. Trong t\u1ed5ng s\u1ed1 100 s\u1ed1 t\u00ednh t\u1eeb 00 \u0111\u1ebfn 99. Th\u00ec ta c\u00f3 27 s\u1ed1 tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft mi\u1ec1n B\u1eafc. Do \u0111\u00f3 x\u00e1c su\u1ea5t tr\u00fang l\u00f4 s\u1ebd l\u00e0 27%. <\/span>N\u1ebfu trong tr\u01b0\u1eddng h\u1ee3p gi\u1ea3i th\u01b0\u1edfng x\u1ed5 s\u1ed1 kh\u00e1c nhau m\u00e0 s\u1ed1 cu\u1ed1i tr\u00f9ng nhau. Th\u00ec x\u00e1c su\u1ea5t tr\u00fang l\u00f4 ch\u1ec9 c\u00f2n l\u1ea1i l\u00e0 23,76%.<\/span><\/p>\n T\u1eeb x\u00e1c su\u1ea5t tr\u00fang l\u00f4 tr\u00ean, Ta s\u1ebd t\u00ednh x\u00e1c su\u1ea5t th\u1eafng l\u00f4 xi\u00ean nh\u01b0 sau:<\/span><\/p>\n X\u00e1c su\u1ea5t th\u1eafng l\u00f4 xi\u00ean 2 = 23,76% x 23,76% = 5,6%<\/span><\/p>\n X\u00e1c su\u1ea5t th\u1eafng l\u00f4 xi\u00ean 3 = 23,76% x 23,76% x 23,76% = 1,34%<\/span><\/p>\n V\u00e0 X\u00e1c su\u1ea5t th\u1eafng xi\u00ean 4 = 23,76% x 23,76% x 23,76% x 23,76% = 0,32%.<\/span><\/p>\n N\u1ebfu x\u00e1c su\u1ea5t nh\u1ecf h\u01a1n 1% th\u00ec t\u1ef7 l\u1ec7 th\u1eafng l\u00f4 xi\u00ean 4 c\u00f2n kh\u00f3 h\u01a1n c\u1ea3 tr\u00fang \u0111\u1ec1.<\/span><\/p>\n M\u1eb7c d\u00f9 x\u00e1c su\u1ea5t th\u1eafng kh\u00f4ng l\u1edbn ch\u1ec9 0,32%. Nh\u01b0ng nhi\u1ec1u ng\u01b0\u1eddi v\u1eabn ch\u1ecdn \u0111\u00e1nh l\u00f4 xi\u00ean 4 \u0111\u1ec3 ch\u01a1i. V\u00ec sao? B\u1edfi v\u00ec \u0111\u01a1n gi\u1ea3n l\u00e0 khi ch\u01a1i l\u00f4 \u0111\u1ec1 th\u00ec x\u00e1c su\u1ea5t th\u1eafng c\u00e0ng th\u1ea5p th\u00ec s\u1ebd c\u00f3 t\u1ef7 l\u1ec7 tr\u1ea3 th\u01b0\u1edfng c\u00e0ng cao. Do \u0111\u00f3, nhi\u1ec1u ng\u01b0\u1eddi bi\u1ebft l\u00f4 xi\u00ean l\u00e0 g\u00ec v\u00e0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang v\u1eabn th\u00edch ch\u01a1i l\u00f4 xi\u00ean 4. Thay v\u00ec ch\u01a1i l\u00f4 xi\u00ean 1, l\u00f4 xi\u00ean 2 c\u00f3 kh\u1ea3 n\u0103ng tr\u00fang cao h\u01a1n.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n Sau khi \u0111\u00e3 bi\u1ebft \u0111\u01b0\u1ee3c l\u00f4 xi\u00ean l\u00e0 g\u00ec v\u00e0 \u0111\u00e1nh l\u00f4 xi\u00ean n\u00e0o c\u00f3 kh\u1ea3 n\u0103ng tr\u00fang cao. Th\u00ec ti\u1ebfp \u0111\u00e2y s\u1ebd chia s\u1ebb c\u00e1c b\u00ed quy\u1ebft c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean d\u1ec5 tr\u00fang nh\u1ea5t. C\u00f9ng v\u1edbi c\u00e1ch t\u00ednh ti\u1ec1n khi th\u1eafng c\u1ee7a t\u1eebng lo\u1ea1i.<\/span><\/p>\n B\u01b0\u1edbc 1. Ch\u1ecdn 2 s\u1ed1 l\u00f4 \u0111\u1eb9p b\u1ea1n \u01b0ng \u00fd nh\u1ea5t. M\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99<\/span><\/p>\n B\u01b0\u1edbc 2. B\u00e1o \u0111\u00e1nh 2 s\u1ed1 l\u00f4 xi\u00ean 2 m\u00e0 b\u1ea1n mu\u1ed1n \u0111\u00e1nh v\u1edbi nh\u00e0 c\u00e1i.<\/span><\/p>\n V\u00ed d\u1ee5. N\u1ebfu b\u1ea1n \u0111\u00e1nh 10 \u2013 04 lo xi\u00ean 2 \u0111\u00e0i H\u00e0 N\u1ed9i v\u1edbi 100000 vn\u0111<\/span><\/p>\n B\u01b0\u1edbc 3 \u2013 C\u00e1ch d\u00f2 l\u00f4 xi\u00ean 2: B\u1ea1n d\u1ef1a v\u00e0o 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng. T\u1ed5ng c\u1ed9ng l\u00e0 27 l\u00f4 gi\u1ea3i c\u1ee7a x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc, 18 l\u00f4 gi\u1ea3i c\u1ee7a x\u1ed5 s\u1ed1 Mi\u1ec1n Trung v\u00e0 x\u1ed5 s\u1ed1 Mi\u1ec1n Nam. N\u1ebfu c\u1ea3 2 s\u1ed1 l\u00f4 n\u00e0y tr\u00f9ng v\u1edbi s\u1ed1 b\u1ea1n \u0111\u00e1nh th\u00ec b\u1ea1n th\u1eafng.<\/span><\/p>\n V\u1edbi t\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 2 l\u00e0 1 \u0103n 10. Th\u00ec b\u1ea1n \u0111\u00e1nh 100.000 \u0111\u1ed3ng v\u00e0 th\u1eafng th\u00ec b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c 100.000 x 10 = 1000.000 \u0111\u1ed3ng.<\/span><\/p>\n B\u01b0\u1edbc 1. Ch\u1ecdn 3 s\u1ed1 l\u00f4 b\u1ea1n \u01b0ng \u00fd, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99<\/span><\/p>\n B\u01b0\u1edbc 2. B\u00e1o \u0111\u00e1nh 3 s\u1ed1 n\u00e0y v\u1edbi l\u00f4 xi\u00ean 3 v\u1edbi nh\u00e0 c\u00e1i.<\/span><\/p>\n V\u00ed d\u1ee5. B\u1ea1n \u0111\u00e1nh 50.000 \u0111\u1ed3ng cho l\u00f4 xi\u00ean 3 v\u1edbi 3 s\u1ed1 13\u201344\u201377 c\u1ee7a cho \u0111\u00e0i x\u1ed5 s\u1ed1 H\u00e0 N\u1ed9i.<\/span><\/p>\n B\u01b0\u1edbc 3. C\u00e1ch d\u00f2 l\u00f4 xi\u00ean 3: xem 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng. N\u1ebfu c\u1ea3 3 s\u1ed1 l\u00f4 b\u1ea1n ch\u1ecdn \u0111\u1ec1u v\u1ec1 th\u00ec b\u1ea1n th\u1eafng.<\/span><\/p>\n B\u01b0\u1edbc 1. Ch\u1ecdn 4 s\u1ed1 l\u00f4 d\u1ec5 tr\u00fang nh\u1ea5t b\u1ea1n \u01b0ng \u00fd, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99<\/span><\/p>\n B\u01b0\u1edbc 2. B\u00e1o v\u1edbi nh\u00e0 c\u00e1i b\u1ea1n \u0111\u00e1nh 4 s\u1ed1 \u0111\u00f3 v\u1edbi l\u00f4 xi\u00ean 4<\/span><\/p>\n V\u00ed d\u1ee5: \u0110\u00e1nh 100000 vn\u0111 cho 4 s\u1ed1 32 \u2013 76 \u2013 81 \u2013 40 v\u1edbi \u0111\u00e0i x\u1ed5 s\u1ed1 H\u1ed3 Ch\u00ed Minh.<\/span><\/p>\n B\u01b0\u1edbc 3 \u2013 C\u00e1ch d\u00f2 l\u00f4 xi\u00ean 4: B\u1ea1n xem 2 s\u1ed1 cu\u1ed1i c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. N\u1ebfu c\u1ea3 4 con l\u00f4 b\u1ea1n ch\u1ecdn \u0111\u1ec1u v\u1ec1 th\u00ec b\u1ea1n th\u1eafng.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n <\/p>\n Xem ngay c\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean \u0111\u1ec3 bi\u1ebft l\u00f4 xi\u00ean \u0103n 2 \u0103n bao nhi\u1ec1u ti\u1ec1n, l\u00f4 xi\u00ean 3 \u0103n bao nhi\u00eau. T\u1eeb \u0111\u00f3 ch\u1ecdn s\u1ed1 ti\u1ec1n \u0111\u1eb7t c\u01b0\u1ee3c cho c\u1eb7p l\u00f4 xi\u00ean \u0111\u1eb9p nh\u1ea5t h\u00f4m nay<\/span><\/p>\n L\u00f4 xi\u00ean 2 : 1 \u0103n 10<\/span><\/p>\n \u0110\u00e1nh 10.000 vnd \u0111\u01b0\u1ee3c 100.000 vnd<\/span><\/p>\n L\u00f4 xi\u00ean 3: 1 \u0103n 40<\/span><\/p>\n \u0110\u00e1nh 10.000 vnd \u0103n 400.000 vnd<\/span><\/p>\n L\u00f4 xi\u00ean 4: 1 \u0103n 400<\/span><\/p>\n \u0110\u00e1nh 10.000 vnd \u0103n 4.000.000 vnd<\/span><\/p>\n Ch\u00fa \u00fd: M\u1ed9t s\u1ed1 nh\u00e0 c\u00e1i c\u00f3 \u0111\u01b0a ra t\u1ef7 l\u1ec7 \u0103n r\u1ea5t cao. Nh\u01b0 l\u00f4 xi\u00ean 2 \u0111\u00e1nh 1 \u0103n 300, 400 th\u1eadm ch\u00ed l\u00ean \u0111\u1ebfn 1000. Th\u00ec \u0111\u1ec1u l\u00e0 nh\u1eefng nh\u00e0 c\u00e1i l\u1eeba \u0111\u1ea3o. B\u1edfi n\u1ebfu t\u1ef7 l\u1ec7 \u0103n nh\u01b0 v\u1eady th\u00ec nh\u00e0 c\u00e1i s\u1ebd l\u1ed7 v\u00e0 kh\u00f4ng nh\u00e0 c\u00e1i n\u00e0o d\u1ea1i g\u00ec \u0111\u1ec3 b\u1ea1n th\u1eafng v\u1edbi t\u1ef7 l\u1ec7 \u0103n n\u00e0y. N\u00ean c\u00e1c b\u1ea1n c\u1ea7n ph\u1ea3i ch\u00fa \u00fd khi l\u1ef1a ch\u1ecdn nh\u00e0 c\u00e1i \u0111\u1ec3 ch\u01a1i.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n Tr\u01b0\u1edbc khi ch\u1ecdn nh\u1eefng con s\u1ed1 \u0111\u1eb9p \u0111\u1ec3 \u0111\u00e1nh. Th\u00ec b\u1ea1n n\u00ean tham kh\u1ea3o nh\u1eefng quy lu\u1eadt m\u00e0 c\u00e1c con l\u00f4 hay sau. \u0110\u1ec3 c\u00f3 th\u1ec3 ch\u1ecdn \u0111\u01b0\u1ee3c con l\u00f4 xi\u00ean hay v\u1ec1 chu\u1ea9n nh\u1ea5t sau khi tham kh\u1ea3o l\u00f4 xi\u00ean l\u00e0 g\u00ec.<\/span><\/p>\n C\u00e1c con l\u00f4 hay \u0111i k\u00e8m nhau: 373 \u2013 010, 25\/52 \u2013 22, 76 \u2013 47, 11 \u2013 44, 66 \u2013 33.<\/span><\/p>\n H\u00f4m nay l\u00f4 v\u1ec1 c\u1ea3 c\u1eb7p 060 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 1 con l\u1ea1i v\u1ec1<\/span><\/p>\n H\u00f4m nay l\u00f4 v\u1ec1 con 51 th\u00ec h\u00f4m sau s\u1ebd ra con 15<\/span><\/p>\n C\u1eb7p 050 ho\u1eb7c h\u00f4m tr\u01b0\u1edbc 1 con \u0111\u00f3 v\u1ec1. H\u00f4m sau th\u01b0\u1eddng s\u1ebd tr\u1ea3 l\u1ea1i 1 con<\/span><\/p>\n C\u1eb7p 020 ho\u1eb7c h\u00f4m tr\u01b0\u1edbc 1 con \u0111\u00f3 v\u1ec1. H\u00f4m sau s\u1ebd v\u1ec1 con 99 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i.<\/span><\/p>\n H\u00f4m nay v\u1ec1 con l\u00f4 75 th\u00ec ng\u00e0y h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 57<\/span><\/p>\n H\u00f4m nay v\u1ec1 con l\u00f4 97 th\u00ec ng\u00e0y h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 3 c\u00e0ng 373<\/span><\/p>\n <\/p>\n L\u00f4 \u0111\u1ea7u 7 ho\u1eb7c l\u00f4 \u0111\u00edt 3 c\u00e2m th\u00ec h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 73<\/span><\/p>\n H\u00f4m nay xu\u1ea5t hi\u1ec7n con l\u00f4 18. H\u00f4m sau s\u1ebd v\u1ec1 con l\u00f4 97, 99 ho\u1eb7c ng\u01b0\u1ee3c l\u1ea1i<\/span><\/p>\n H\u00f4m nay xu\u1ea5t hi\u1ec7n con l\u00f4 45, h\u00f4m sau s\u1ebd v\u1ec1 l\u00f4 595 ho\u1eb7c 09<\/span><\/p>\n Con l\u00f4 58 xu\u1ea5t hi\u1ec7n th\u00ec 3 ng\u00e0y sau s\u1ebd c\u00f3 con l\u00f4 63<\/span><\/p>\n H\u00f4m nay ra l\u00f4 68 th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 con l\u00f4 86<\/span><\/p>\n \u0110\u1ec1 v\u1ec1 05 th\u00ec h\u00f4m sau s\u1ebd xu\u1ea5t hi\u1ec7n con l\u00f4 95<\/span><\/p>\n \u0110\u1ec1 v\u1ec1 29 th\u00ec ng\u00e0y h\u00f4m sau s\u1ebd c\u00f3 con l\u00f4 22 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i<\/span><\/p>\n C\u00e1c con l\u00f4 hay v\u1ec1 h\u00e0ng ng\u00e0y: 373, 565, 75, 79, 92<\/span><\/p>\n V\u00e0o th\u1ee9 5 v\u00e0 th\u1ee9 7 con l\u00f4 97 hay ra<\/span><\/p>\n V\u00e0o th\u1ee9 7, ch\u1ee7 nh\u1eadt, th\u1ee9 2, th\u1ee9 3 con l\u00f4 33 hay ra<\/span><\/p>\n Th\u1ee9 4, th\u1ee9 5, th\u1ee9 6 con l\u00f4 66 hay ra<\/span><\/p>\n H\u00f4m tr\u01b0\u1edbc \u0111\u1ec1 v\u1ec1 k\u00e9p 00, 11, 22 \u2026 99. Th\u00ec ng\u00e0y h\u00f4m sau s\u1ebd c\u00f3 1 trong nh\u1eefng con l\u00f4 sau: 010, 151, 060, 565. V\u00e0 sau \u0111\u00f3 1 tu\u1ea7n s\u1ebd v\u1ec1 nh\u1eefng con l\u00f4 232, 282, 373, 787.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n N\u1ed9i dung tr\u00ean \u0111\u00e2y gi\u1ea3i th\u00edch v\u1ec1 l\u00f4 xi\u00ean l\u00e0 g\u00ec. C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang khi \u0111\u00e1nh l\u00f4 xi\u00ean c\u00f9ng t\u1ef7 l\u1ec7 \u0103n c\u01b0\u1ee3c t\u1eebng lo\u1ea1i c\u1ee5 th\u1ec3. C\u00f9ng c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean v\u00e0 kinh nghi\u1ec7m ch\u01a1i th\u1eafng l\u00f4 xi\u00ean \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi \u00e1p d\u1ee5ng nh\u1ea5t. <\/span>Ch\u00fac b\u1ea1n soi c\u1ea7u ch\u00ednh x\u00e1c, ch\u1ed1t s\u1ed1 \u0111\u1eb9p v\u00e0 th\u1eafng l\u1edbn.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n <\/main><\/div>\nL\u00f4 xi\u00ean l\u00e0 g\u00ec?<\/span><\/h3>\n
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean<\/span><\/h3>\n
C\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean d\u1ec5 tr\u00fang nh\u1ea5t<\/span><\/h3>\n
C\u00e1ch \u0111\u00e1nh L\u00f4 xi\u00ean 2:<\/span><\/h3>\n
C\u00e1ch \u0111\u00e1nh L\u00f4 xi\u00ean 3<\/span><\/h3>\n
C\u00e1ch \u0111\u00e1nh L\u00f4 xi\u00ean 4<\/span><\/h3>\n
C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean<\/span><\/h2>\n
Kinh nghi\u1ec7m soi c\u1ea7u l\u00f4 xi\u00ean<\/span><\/h2>\n
C\u00e1c con l\u00f4 th\u01b0\u1eddng ra k\u00e8m nhau<\/span><\/h3>\n
C\u00e1c con l\u00f4 th\u01b0\u1eddng ra theo ng\u00e0y<\/span><\/h3>\n