{"id":18374,"date":"2024-04-02T14:27:58","date_gmt":"2024-04-02T14:27:58","guid":{"rendered":"https:\/\/soicau4072.minhngocxoso.com\/?p=18374"},"modified":"2024-04-02T14:27:58","modified_gmt":"2024-04-02T14:27:58","slug":"cach-tinh-xac-suat-lo-xien-2-xien-3","status":"publish","type":"post","link":"https:\/\/soicauhcmvip.com\/cach-tinh-xac-suat-lo-xien-2-xien-3\/","title":{"rendered":"c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2 xi\u00ean 3"},"content":{"rendered":"

C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2<\/h2>\n

Ch\u1ecdn 2 s\u1ed1 l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 k\u1ebft h\u1ee3p th\u00e0nh 1 c\u1eb7p.<\/p>\n

Trong c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2, t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0103n 10 t\u1ee9c l\u00e0 b\u1ea1n c\u01b0\u1ee3c 1.000 \u0111\u1ed3ng cho c\u1eb7p xi\u00ean \u0111\u00f4i th\u00ec khi tr\u00fang b\u1ea1n s\u1ebd l\u0129nh 10.000 \u0111\u1ed3ng.<\/p>\n

L\u00f4 xi\u00ean \u0111\u00f4i ch\u1ec9 \u0111\u01b0\u1ee3c coi l\u00e0 tr\u00fang th\u01b0\u1edfng n\u1ebfu 2 con l\u00f4 b\u1ea1n ch\u1ecdn \u0111\u1ed3ng th\u1eddi v\u1ec1 trong c\u00f9ng m\u1ed9t ng\u00e0y quay th\u01b0\u1edfng.<\/p>\n

C\u00e1ch d\u00f2 th\u1eafng l\u00f4 xi\u00ean 2: b\u1ea1n d\u1ef1a v\u00e0o 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng \u1edf c\u00e1c \u0111\u00e0i B\u1eafc \u2013 Trung \u2013 Nam.<\/p>\n

C\u1ea3 2 s\u1ed1 l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi s\u1ed1 l\u00f4 b\u1ea1n ch\u1ecdn.<\/p>\n

V\u00ed d\u1ee5: l\u00f4 xi\u00ean 2: 20-02 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i hay l\u00f4 xi\u00ean 2 52-59 c\u1ee7a \u0111\u00e0i HCM.<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2<\/h2>\n

V\u00ed d\u1ee5:<\/p>\n

N\u1ebfu trong b\u1ea3ng k\u1ebft qu\u1ea3 c\u1ee7a \u0111\u00e0i ch\u1ecdn c\u00f3 27 gi\u1ea3i  th\u01b0\u1edfng th\u00ec k\u1ebft qu\u1ea3 l\u00f4 l\u00e0 nh\u1eefng con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a 27 s\u1ed1 \u0111\u00f3.<\/p>\n

T\u1ee9c l\u00e0 trong 100 s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 th\u00ec c\u00f3 27 s\u1ed1 tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 s\u1ed5 x\u1ed1. V\u1eady x\u00e1c xu\u1ea5t tr\u00fang l\u00f4 cao nh\u1ea5t l\u00e0 27%.<\/p>\n

Trong tr\u01b0\u1eddng h\u1ee3p gi\u1ea3i th\u01b0\u1edfng \u1edf c\u00e1c m\u1ee5c gi\u1ea3i th\u01b0\u1edfng kh\u00e1c nhau m\u00e0 c\u00f3 nh\u1eefng s\u1ed1 cu\u1ed1i tr\u00f9ng nhau th\u00ec x\u00e1c su\u1ea5t tr\u00fang gi\u1ea3m \u0111i. Theo th\u1ef1c t\u1ebf , b\u1ec9nh qu\u00e2n ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau.<\/p>\n

V\u00ec v\u1eady, c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2 l\u00e0 = 21,5% x 21,5% = 0,046. T\u1ee9c l\u00e0 x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang l\u00e0 4,6%.<\/p>\n

T\u01b0\u01a1ng t\u1ef1 v\u1edbi c\u00e1c xi\u00ean 3, xi\u00ean 4<\/p>\n

Qua c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2 tr\u00ean c\u00f3 th\u1ec3 th\u1ea5y mu\u1ed1n th\u1eafng b\u1ea1n c\u1ea7n ph\u1ea3i chu\u1ea9n b\u1ecb m\u1ed9t s\u1ed1 v\u1ed1n \u0111\u1ee7 v\u00e0 h\u1ee3p l\u00fd \u0111\u1ec3 \u0111\u1ec1 ph\u00f2ng r\u1ee7i ro m\u1ea5t \u0111i s\u1ed1 ti\u1ec1n c\u01b0\u1ee3c ho\u00e0n to\u00e0n.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4:<\/h4>\n

\"\"<\/p>\n

\u1ede mi\u1ec1n B\u1eafc, v\u1edbi m\u1ed7i m\u1ed9t \u0111i\u1ec3m l\u00f4 tr\u00fang, ng\u01b0\u1eddi ch\u01a1i s\u1ebd thu v\u1ec1 s\u1ed1 ti\u1ec1n t\u01b0\u01a1ng \u1ee9ng l\u00e0 80.000 \u0111\u1ed3ng. N\u1ebfu trong ng\u00e0y h\u00f4m \u0111\u00f3 c\u00f3 nhi\u1ec1u gi\u1ea3i c\u00f3 2 s\u1ed1 cu\u1ed1i tr\u00f9ng v\u1edbi s\u1ed1 b\u1ea1n \u0111\u00e3 ghi l\u00e0 n l\u1ea7n th\u00ec b\u1ea1n s\u1ebd nh\u1eadn s\u1ed1 ti\u1ec1n th\u01b0\u1edfng = 80.000*n.<\/p>\n

M\u1ed9t ng\u01b0\u1eddi ch\u01a1i l\u00f4 b\u00ecnh qu\u00e2n \u0111\u00e1nh 2 \u2013 3 s\u1ed1, ch\u1ec9 c\u1ea7n tr\u00fang 1 s\u1ed1 l\u00e0 c\u00f3 l\u00e3i r\u1ed3i. Khi \u0111\u00e1nh h\u00e3y \u0111\u00e1nh ch\u1eafc ch\u1eafn v\u00e0 t\u1ef1 tin v\u00e0o b\u1ea3n th\u00e2n m\u00ecnh. N\u1ebfu th\u1ea5y kh\u1ea3 n\u0103ng th\u1eafng c\u00f2n xa th\u00ec ch\u1ec9 n\u00ean \u0111\u00e1ng \u00e1ng ch\u1eebng, t\u1eebng ch\u00fat m\u1ed9t. Khi kh\u1ea3 n\u0103ng th\u1eafng cao th\u00ec \u0111\u00e1nh l\u1edbn \u0111\u1ec3 l\u1ea5y l\u1ea1i nh\u1eefng g\u00ec \u0111\u00e3 m\u1ea5t. Bi\u1ebft d\u1eebng l\u1ea1i \u0111\u00fang l\u00fac khi g\u1eb7p v\u1eadn \u0111en \u0111ang theo ch\u00e2n m\u00ecnh \u0111\u1ec3 b\u1ea3o to\u00e0n kinh t\u1ebf c\u1ee7a b\u1ea1n. Hi v\u1ecdng b\u1ea1n \u0111\u1eebng \u0111\u1eb7t n\u1eb7ng chuy\u1ec7n th\u1eafng thua.<\/p>\n

C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 3<\/h2>\n

B\u01b0\u1edbc 1: B\u1ea1n ch\u1ecdn 3 s\u1ed1 l\u00f4, m\u1ed7i s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 t\u1eeb  2 ch\u1eef s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 k\u1ebft h\u1ee3p th\u00e0nh m\u1ed9t l\u00f4 xi\u00ean 3.<\/p>\n

B\u01b0\u1edbc 2: d\u00f2 s\u1ed1 : b\u1ea1n d\u1ef1a v\u00e0o 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i th\u01b0\u1edfng \u1edf c\u00e1c \u0111\u00e0i B\u1eafc- Trung -Nam<\/p>\n

C\u1ea3 3 s\u1ed1 l\u00f4 n\u00e0y ph\u1ea3i tr\u00f9ng v\u1edbi s\u1ed1 l\u00f4 b\u1ea1n ch\u1ecdn<\/h4>\n

V\u00ed d\u1ee5: l\u00f4 xi\u00ean 3 : 20-02-04 c\u1ee7a \u0111\u00e0i H\u00e0 N\u1ed9i hay l\u00f4 xi\u00ean 3: 52-59-69 c\u1ee7a \u0111\u00e0i HCM<\/p>\n

L\u01b0u \u00fd: Trong c\u00e1ch t\u00ednh l\u00f4 xi\u00ean 3,  t\u1ef7 l\u1ec7 \u0103n \u1edf c\u00e1c nh\u00e0 c\u00e1i l\u00e0 kh\u00e1c nhau.<\/p>\n

T\u1ec9 l\u1ec7 tr\u1ea3 th\u01b0\u1edfng c\u1ee7a nh\u00e0 c\u00e1i l\u00e0 l\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc : 1 \u0103n 65, xi\u00ean 3 mi\u1ec1n nam l\u00e0 1 \u0103n 135<\/p>\n

Th\u00ec t\u1ee9c l\u00e0 b\u1ea1n \u0111\u00e1nh 100k \u0103n 6.500.000\u0111 (MB)<\/p>\n

L\u00f4 xi\u00ean ba ch\u1ec9 \u0111\u01b0\u1ee3c coi l\u00e0 tr\u00fang th\u01b0\u1edfng ch\u1ec9 khi 3 con l\u00f4 b\u1ea1n ch\u1ecdn \u0111\u1ed3ng th\u1eddi v\u1ec1 trong c\u00f9ng m\u1ed9t ng\u00e0y quay th\u01b0\u1edfng.<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/h2>\n

V\u00ed d\u1ee5:<\/p>\n

N\u1ebfu trong b\u1ea3ng k\u1ebft c\u1ee7a c\u1ee7a \u0111\u00e0i ch\u1ecdn c\u00f3 27 gi\u1ea3i  th\u01b0\u1edfng th\u00ec k\u1ebft qu\u1ea3 l\u00f4 l\u00e0 nh\u1eefng con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a 27 s\u1ed1 \u0111\u00f3.<\/p>\n

T\u1ee9c l\u00e0 trong 100 s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99 th\u00ec c\u00f3 27 s\u1ed1 tr\u00f9ng v\u1edbi k\u1ebft qu\u1ea3 s\u1ed5 x\u1ed1. V\u1eady x\u00e1c xu\u1ea5t tr\u00fang l\u00f4 cao nh\u1ea5t l\u00e0 27%.<\/p>\n

Trong tr\u01b0\u1eddng h\u1ee3p gi\u1ea3i th\u01b0\u1edfng \u1edf c\u00e1c m\u1ee5c gi\u1ea3i th\u01b0\u1edfng kh\u00e1c nhau m\u00e0 c\u00f3 nh\u1eefng s\u1ed1 cu\u1ed1i tr\u00f9ng nhau th\u00ec x\u00e1c su\u1ea5t tr\u00fang gi\u1ea3m \u0111i. Theo th\u1ef1c t\u1ebf , b\u1ec9nh qu\u00e2n ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau.<\/p>\n

Do \u0111\u00f3, ta c\u00f3 c\u00e1c c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t:<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2 l\u00e0 = 21,5% x 21,5% =0,046 \u2013 T\u1ee9c  l\u00e0 x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang l\u00e0 4,6%<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 3 l\u00e0 : 21,5% x 21,5% x 21,5% = 0,0994 \u2013 T\u1ee9c l\u00e0 x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang c\u1ee7a l\u00f4 xi\u00ean 3 l\u00e0 0,994%<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean 3 (tham kh\u1ea3o)<\/h2>\n

\"\"<\/p>\n

\u1ede mi\u1ec1n B\u1eafc, v\u1edbi m\u1ed7i m\u1ed9t \u0111i\u1ec3m l\u00f4 tr\u00fang, ng\u01b0\u1eddi ch\u01a1i s\u1ebd thu v\u1ec1 s\u1ed1 ti\u1ec1n t\u01b0\u01a1ng \u1ee9ng.<\/p>\n

S\u1ed1 ti\u1ec1n n\u00e0y t\u00f9y thu\u1ed9c v\u00e0o s\u1ed1 ti\u1ec1n nh\u00e0 c\u00e1i h\u1ee9a tr\u1ea3 th\u01b0\u1edfng ban \u0111\u1ea7u. N\u1ebfu nh\u00e0 c\u00e1i h\u1ee9a tr\u1ea3 th\u01b0\u1edfng 1 \u0103n 65 th\u00ec s\u1ed1 ti\u1ec1n b\u1ea1n nh\u1eadn \u0111\u01b0\u1ee3c cho m\u1ed7i xi\u00ean 3 th\u1eafng l\u00e0 65<\/p>\n

N\u1ebfu trong ng\u00e0y h\u00f4m \u0111\u00f3 c\u00f3 nhi\u1ec1u gi\u1ea3i c\u00f3 2 s\u1ed1 cu\u1ed1i tr\u00f9ng v\u1edbi s\u1ed1 b\u1ea1n \u0111\u00e3 ghi l\u00e0 n l\u1ea7n th\u00ec b\u1ea1n s\u1ebd nh\u1eadn s\u1ed1 ti\u1ec1n th\u01b0\u1edfng = 65*n.<\/p>\n

K\u1ebft lu\u1eadn<\/h2>\n

Tr\u00ean \u0111\u00e2y l\u00e0 b\u00e0i vi\u1ebft gi\u1edbi thi\u1ec7u v\u1ec1 l\u00f4 xi\u00ean, l\u00f4 xi\u00ean l\u00e0 g\u00ec? C\u00e1ch ch\u01a1i l\u00f4 xi\u00ean 2 nh\u01b0 th\u1ebf n\u00e0o? C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 2 v\u00e0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2. Mong b\u1ea1n c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng th\u00e0nh c\u00f4ng trong \u0111\u00e1nh l\u00f4, \u0111\u1ec1. Ch\u00fac b\u1ea1n g\u1eb7p nhi\u1ec1u may m\u1eafn khi ch\u01a1i v\u1edbi h\u00ecnh th\u1ee9c n\u00e0y.<\/p>\n

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